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Show that the points A(1,2,3), B(-1,-2,-1), C(2,3,2), D(4,7,6) are the vertices of a parallelogram.

A

`x/1 = y/2 = z/2`

B

`(x+2)/1 = (y+3)/(2) = (z-3)/2`

C

`x/2=(y)/3=z/2`

D

`(x-2)/1=(y-3)/2 =(z-2)/2`

Text Solution

Verified by Experts

The correct Answer is:
D
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DISHA PUBLICATION-THREE DIMENSIONAL GEOMETRY -Exercise -2 : Concept Applicator
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  3. Show that the points A(1,2,3), B(-1,-2,-1), C(2,3,2), D(4,7,6) are the...

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  4. The shortest distance between the line 1+x=2y=-12z and x=y+2=6z-6 is

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  6. The angle between the lines (x+1)/2 = (y+3)/2 = (z-4)/-1 and (x-4)/1 =...

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  7. The distance between the line given by vecr= hati+hatj + lamda(hati-2...

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  10. If A,B,C are point (1,0,4) , (0,-1,5) and (2,-3,1) respectively , then...

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  13. The plane ax+by=0 is rotated through an angle alpha about its line of ...

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  14. The plane x + 3y + 13 = 0 passes through the line of intersection of t...

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  15. A variable plane at distance of 1 unit from the origin cuts the coordi...

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  16. If the angle theta between the line (x+1)/1=(y-1)/2=(z-2)/2 and the pl...

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  17. The equation of the line passing through (1, 1, 1) and perpendicular t...

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  18. If the distance between the plane Ax 2y + z = d and the plane contain...

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  19. If the angle between the line x=(y-1)/(2)=(z-3)(lambda) and the plane ...

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  20. If two points are P(7, -5, 11) and Q(-2, 8, 13), then the projection o...

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