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If two points are P(7, -5, 11) and Q(-2,...

If two points are `P(7, -5, 11) and Q(-2, 8, 13)`, then the projection of PQ on a straight line with direction cosines `(1)/(2), (2)/(3),(2)/(3)` is

A

`(1)/(2)`

B

`(26)/(3)`

C

`(4)/(3)`

D

6

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The correct Answer is:
To find the projection of the line segment joining the points \( P(7, -5, 11) \) and \( Q(-2, 8, 13) \) onto a straight line with direction cosines \( \left( \frac{1}{2}, \frac{2}{3}, \frac{2}{3} \right) \), we can follow these steps: ### Step 1: Find the coordinates of points P and Q The coordinates of point \( P \) are \( (7, -5, 11) \) and the coordinates of point \( Q \) are \( (-2, 8, 13) \). ### Step 2: Calculate the vector \( \overrightarrow{PQ} \) The vector \( \overrightarrow{PQ} \) can be calculated using the formula: \[ \overrightarrow{PQ} = Q - P = (-2 - 7, 8 - (-5), 13 - 11) \] Calculating each component: \[ \overrightarrow{PQ} = (-9, 13, 2) \] ### Step 3: Identify the direction cosines The direction cosines of the line are given as: \[ l = \frac{1}{2}, \quad m = \frac{2}{3}, \quad n = \frac{2}{3} \] ### Step 4: Use the projection formula The projection of the vector \( \overrightarrow{PQ} \) onto the line with direction cosines \( (l, m, n) \) is given by the formula: \[ \text{Projection} = \overrightarrow{PQ} \cdot (l, m, n) \] Calculating the dot product: \[ \text{Projection} = (-9) \cdot \frac{1}{2} + (13) \cdot \frac{2}{3} + (2) \cdot \frac{2}{3} \] ### Step 5: Calculate each term Calculating each term separately: 1. \( -9 \cdot \frac{1}{2} = -\frac{9}{2} \) 2. \( 13 \cdot \frac{2}{3} = \frac{26}{3} \) 3. \( 2 \cdot \frac{2}{3} = \frac{4}{3} \) ### Step 6: Combine the results Now, we combine these results: \[ \text{Projection} = -\frac{9}{2} + \frac{26}{3} + \frac{4}{3} \] ### Step 7: Find a common denominator The common denominator for \( 2 \) and \( 3 \) is \( 6 \): - Convert \( -\frac{9}{2} \) to sixths: \[ -\frac{9}{2} = -\frac{27}{6} \] - Convert \( \frac{26}{3} \) to sixths: \[ \frac{26}{3} = \frac{52}{6} \] - Convert \( \frac{4}{3} \) to sixths: \[ \frac{4}{3} = \frac{8}{6} \] ### Step 8: Combine the fractions Now we can combine: \[ \text{Projection} = -\frac{27}{6} + \frac{52}{6} + \frac{8}{6} = \frac{-27 + 52 + 8}{6} = \frac{33}{6} = \frac{11}{2} \] ### Final Answer Thus, the projection of \( PQ \) on the given line is: \[ \frac{11}{2} \]
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DISHA PUBLICATION-THREE DIMENSIONAL GEOMETRY -Exercise -2 : Concept Applicator
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