In Carcuc method for the estimation of halogens. 250 mg of organic compound gave 141 mg of `AgBr`. The percentage of bromine in the compound is :

Options

A. 48
B. 60
C. 24
D. 36

Answer

C

Explanation

Mass of substance = 250 mg = 0.250 g
Mass of AgBr = 141 mg = 0.141 g
1 mole of AgBr = 1 g atom of Br
188 g of AgBr = 80 g of Br
`:.` 188 g of AgBr contain bromine = 80 g
`:. "0.141 g of AgBr contain bromine"=(80)/(188) xx 0.141`
This much amount of bromine present in 0.250 g of organic compound
`:. "% of bromine"=(88)/(188) xx (0.414)/(0.250) xx 100= 24%`