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The ratio of number of oxygen atoms (O) ...

The ratio of number of oxygen atoms `(O)` in `16.0g` ozone `(O_(3)) . 28.0g` carbon monoxide `(CO)` and `32.0g` oxygen `(O_(2))` is :-
`("Atomic mass" : C=12,O=16 "and Avogadro's constant" N_(A) =6.0xx10^(23) "mol"^(-1))`

A

` 3 : 1 : 2`

B

` 1 : 1 : 2`

C

` 3 : 1 : 1`

D

` 1 : 1 : 1`

Text Solution

Verified by Experts

The correct Answer is:
B
` 1 : 1 : 2`
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