The number of gram molecules of oxygen in `6.02 xx 10^(24) CO` molecules is

Options

A. 10 g molecules
B. 5 g molecules
C. 1 g molecules
D. 0.5 g molelcules

Explanation

To find the number of gram molecules of oxygen in \(6.02 \times 10^{24}\) molecules of carbon monoxide (CO), we can follow these steps:

### Step 1: Determine the number of moles of carbon monoxide (CO)
Using Avogadro's number, we know that:
\[ 1 \text{ mole} = 6.02 \times 10^{23} \text{ molecules} \]
To find the number of moles of CO in \(6.02 \times 10^{24}\) molecules, we can use the formula:
\[ \text{Number of moles} = \frac{\text{Number of molecules}}{6.02 \times 10^{23}} \]
Substituting the given value:
\[ \text{Number of moles of CO} = \frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} = 10 \text{ moles} \]

### Step 2: Determine the number of moles of oxygen (O2)
Each molecule of carbon monoxide (CO) contains one atom of oxygen. Therefore, for every mole of CO, there is one mole of oxygen atoms. Since we have 10 moles of CO, we will also have:
\[ \text{Number of moles of oxygen atoms} = 10 \text{ moles} \]

### Step 3: Convert moles of oxygen atoms to moles of molecular oxygen (O2)
Molecular oxygen (O2) consists of two oxygen atoms. Therefore, to find the number of moles of O2, we divide the number of moles of oxygen atoms by 2:
\[ \text{Number of moles of O2} = \frac{\text{Number of moles of oxygen atoms}}{2} = \frac{10}{2} = 5 \text{ moles} \]

### Conclusion
The number of gram molecules of oxygen in \(6.02 \times 10^{24}\) CO molecules is \(5\) moles of O2.

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