The number of molecules in 16 g of methane is

Options

A. `3.0 xx 10^(23)`
B. `(16)/(6.02) xx 10_(23)`
C. `6.023 xx 10^(23)`
D. `(16)/(3.0) xx 10^(23)`

Answer

C

Explanation

16 g `CH_(4)` is 1 mol. Hence number of molecules = `"Avogadro number" =6.023 xx 10^(23)`