25.4 gm of iodine and 14.2 gm of chlorine are made to react completely ot yield mixture of ICI and `ICI_(3)` Ratio of moles of ICI & `ICI_(3)` formed is (Atomic mass I: 127, Cl=35.5)

Options

A. 0.1, 0.1
B. 0.2, 0.2
C. 0.1, 0.2
D. 0.2, 0.1

Answer

A

Explanation

Initial mole of `I_(2) =(25.4)/(257) = 0.1` mole
Initial mole of `Cl_(2) =(14.2)/(71)=0.2` mole
`I_(2)+2Cl_(2) to ICl+ICl_(3)`
Initially `" "0" "0`
After reaction `" "0.1" "0.1`