Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will be

Options

A. 0.6 moles
B. 0.4 moles
C. 7.5 moles
D. 0.2 moles

Answer

B

Explanation

`underset("oxalate ion")(5underset(COO^(-))overset(COO^(-))(|))+2MnO_(4)^(-)+16H^(+) to 2 Mn^(2+)+10CO_(2)+8H_(2)O`
From above equation 2 moles `MnO_(4)` required to oxide 5 moles of oxalate.
Thus number of moles of `MnO_(4)` required to oxidise one mole of oxalate `=2 // 5 =0.4`