How many moles of `P_(4)O_(6)` and `P_(4)O_(10)` will be produced by the combustion of 12.4 g of phosphorous (atomic mass 31) in 12.8 g ofoxygen, leaving no `P_(4)` or `O_(2)` ?

Options

A. 0.1 and 0.3 mol
B. 0.15 mol and 0.25 mol
C. 0.05 mol each
D. 0.1 mol each

Answer

C

Explanation

Moles of `P_(4)= (12.4)/(4 xx 31) = 0.1`
Moles of `O_(2)= (12.8)/(32)=0.4`
Let x moles of `P_(4)` from `P_(4)O_(6)` .
Then, moles of `O_(2)` required `= x xx 3+(0.1- x) xx 5=0.4`
(given) `implies x = 0.05`