`6.02xx10^(20)` molecules of urea are present in 100 ml of its solution. The concentration of solution is :

Options

A. 0.01 M
B. 0.001 M
C. 0.1 M
D. 0.02 M

Answer

A

Explanation

`M=(6.02 xx 10^(20) xx 1000)/(100 xx 6.023 xx 10^(23))=(6.02 xx 10^(21))/(6.02 xx 10^(23))=0.01M`