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If 0.20 g chloride of a certain metal, w...

If 0.20 g chloride of a certain metal, when dissolved in water and treated with excess of `AgNO_(3)` yields 0.50 g of AgCl, the equivalent mass of the metal is (Ag=108, Cl = 35.5)

A

21.9

B

20.04

C

40.08

D

43.80

Text Solution

Verified by Experts

The correct Answer is:
A
`(E+"Eq. mass of" Cl^(-))/("Eq. mass of Ag + Eq. mass of" Cl^(-))=(E+35.5)/(108+35.5)`
`=(0.2)/(0.5) implies E = 21.90`
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