If a pure compound is composed of `X_(2)Y_(3)` molecules and consists of `60%` X by weight what is the atomic weight of Y in term of atomic weight of X (Atomic mass of `X=M_(x)`)?

Options

A. 2.25 times atomic weight of X
B. 44% of atomic weight of X
C. 4.0 times the atomic weight of X
D. 25% of the atomic weight of X

Answer

B

Explanation

Mol of X in 60 g= `(60)/(M_(X))` and mol of Y in 40 g= `(40)/(M_(Y))`
Also, `(n_(x))/(n_(y))=(2)/(3)=(60)/(M_(X)).(M_(Y))/(40)`
`implies Mg =(4)/(9)M_(X) = 44%` of atomic weight of x