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Percentage of Se in peroxidase anhydrase...

Percentage of Se in peroxidase anhydrase enzyme is `0.5%` by weight (at. Wt. `=78.4)`, then minimum molecular weight of peroxidase anhydrase enzyme is:

A

`1.568 xx 10^(3)`

B

15.68

C

`2.136 xx 10^(4)`

D

`1.568 xx 10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
0.5 g of Se=100 g enzyme
`"78.4 g of Se" =(100)/(0.5) xx 78.4 = 1.568 xx 10^(4)g` enzyme
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