Calculate the mass of `BaCO_(3)` produced when excess `CO_(2)` is bubbled through a solution containing `0.205` moles of `Ba(OH)_(2)`.

Options

A. 81 g
B. 40.5 g
C. 20.25 g
D. 162 g

Answer

B

Explanation

`underset("n mol")(Ba(OH)_(2))+CO_(2) to underset("n mol")(BaCO_(3))+H_(2)O`
n mol `Ba(OH)_(2)= "n mol" BaCO_(3)`
`:. 0.205 mol Ba(OH)_(2)-=0.205 mol BaCO_(3)`
`"Wt. of substance"="No. of moles" xx "Molecular mass"`
`=0.205 xx 197.3 =40.5 g`