12 litre of `H_(2)` and 11.2 litre of `Cl_(2)` are mixed and exploded. The composition by volume of mixture is-

Options

A. 11.2, 11.2, 22.4
B. 0.8, 0, 22.4
C. 0.8, 0.8, 22.1
D. 0.8, 11.2, 22.4

Answer

B

Explanation

`underset(underset(11.2 L)(1L))(H_(2))+underset(underset(11.2 L)(1 L))(Cl_(2)) to underset(underset(22.4 L)(3 L))(2HCl)`
Volume of `H_(2)=[12 - 11.2]=0.8 L`,
Volume of `Cl_(2)` = Zero, Volume of HCl = 22.4 L