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If 1 1/2 moles of oxygen combine with Al...

If `1 1/2` moles of oxygen combine with Al to form `Al_(2)O_(3)` the weight of Al used in the reaction is (Al=27)

A

27 g

B

54 g

C

49.5 g

D

31 g

Text Solution

Verified by Experts

The correct Answer is:
B

`2Al+(3)/(2)O_(2) to Al_(2)O_(3)`
According to equation `(3)/(2)` mole of `O_(2)` combines with 2 mole Al.
2 mole Al = 54 g
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