A silver coin weighing 11.34 g was dissolved in nitric acid When sodium chloride was added to the solution all the silver (present as `AgNO_(3)`) precipitated as silver chloride. The mass of the precipitated silver chloride was 14.35 g. Calculate the percentage of silver in the coin.

Options

A. `4.8%`
B. `95.2%`
C. `90%`
D. `80%`

Answer

B

Explanation

`Ag + HNO, to AgNO_(3)`
 `AgNO_(3) + NaCl to NaNO_(3)+AgCl`
Mole of Ag in coin-mole of Ag in Agci
`alpha=(14.35)/(143.5)=0.1` mole
`"Mass of Ag in coin"=0.1 xx 108 = 10.8 g`
`:. "% silver in coin"=(10.8)/(11.34) xx 100%= 95.2%`