An organic compound contains 49.3 % carbon,6.84 % hydrogen and its vapour density is 73 Molecular formula of the compound is

Options

A. `C_(3)H_(5)O_(2)`
B. `C_(4)H_(10)O_(2)`
C. `C_(6)H_(10)O_(4)`
D. `C_(3)H_(10)O_(2)`

Answer

C

Explanation

`:. "Element formula"=C_(3)H_(5)O_(2)`
Emphirical formula mass
`=(3 xx 12)+(5 xx 1)+(2 xx 16)=36+5+32=73`
`"Molecular mass"=2 xx "Vapour density"`
`=2 xx 73=146`
`n=("molecular mass")/("emphirical formula mass")=146 // 73=2`
`"Molecular formula"= "Emphirical formula" xx 2`
`=(C_(3)H_(5)O_(2)) xx 2=C_(6)H_(10)O_(4)`