In the reaction, `4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g)`, when 1 mole of ammonia and 1 mole of `O_(2)` are made to react to completion

Options

A. 1.0 mole of `H_(2)O` is produced
B. 1.0 mole of NO will be produced
C. all the oxygen will be consumed
D. all the ammonia will be consumed

Answer

C

Explanation

According to stoichiometry they should react as follow
`4NH_(3) +5O_(2) ti 4NO+6H_(2)O`
4 mole of `NH_(3)` requires 5 mole of `O_(2)`
1 mole of `NH_(3) "requires" =(5)/(4) = 1.25` mole of `O_(2)`
Hence `O_(2)` is consumed completely.