Home
Class 12
CHEMISTRY
Consider the reaction 2 A+B+3C to P+2Q. ...

Consider the reaction `2 A+B+3C to P+2Q`. Starting with 3 mol of A, 2 mol of B and 6 mol of C, number of moles of the products P and Q would respectively be

A

2 and 4

B

4 and 2

C

3 and 1.5

D

1.5 and 3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the number of moles of products P and Q formed from the given reactants A, B, and C in the reaction: \[ 2A + B + 3C \rightarrow P + 2Q \] **Step 1: Identify the initial moles of reactants.** - Moles of A = 3 - Moles of B = 2 - Moles of C = 6 **Step 2: Determine the stoichiometric coefficients from the balanced equation.** From the balanced equation: - For A: 2 moles are required - For B: 1 mole is required - For C: 3 moles are required **Step 3: Calculate the maximum amount of product that can be formed from each reactant.** 1. **From A:** - According to the reaction, 2 moles of A produce 1 mole of P. - Therefore, 3 moles of A can produce: \[ \text{Moles of P from A} = \frac{3 \text{ moles A}}{2} = 1.5 \text{ moles of P} \] 2. **From B:** - According to the reaction, 1 mole of B produces 1 mole of P. - Therefore, 2 moles of B can produce: \[ \text{Moles of P from B} = 2 \text{ moles of B} = 2 \text{ moles of P} \] 3. **From C:** - According to the reaction, 3 moles of C produce 1 mole of P. - Therefore, 6 moles of C can produce: \[ \text{Moles of P from C} = \frac{6 \text{ moles C}}{3} = 2 \text{ moles of P} \] **Step 4: Identify the limiting reagent.** From the calculations: - A can produce 1.5 moles of P. - B can produce 2 moles of P. - C can produce 2 moles of P. The limiting reagent is the one that produces the least amount of product, which is A (1.5 moles of P). **Step 5: Calculate the amount of Q produced.** From the balanced equation: - 2 moles of A produce 2 moles of Q. - Therefore, 1 mole of A produces 1 mole of Q. - Hence, 3 moles of A will produce: \[ \text{Moles of Q} = 3 \text{ moles of A} = 3 \text{ moles of Q} \] **Final Result:** - Moles of P = 1.5 - Moles of Q = 3 Thus, the number of moles of products P and Q would respectively be **1.5 moles of P and 3 moles of Q**. ---

To solve the problem, we need to determine the number of moles of products P and Q formed from the given reactants A, B, and C in the reaction: \[ 2A + B + 3C \rightarrow P + 2Q \] **Step 1: Identify the initial moles of reactants.** - Moles of A = 3 - Moles of B = 2 - Moles of C = 6 ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    DISHA PUBLICATION|Exercise Exercise|116 Videos
  • STATES OF MATTER

    DISHA PUBLICATION|Exercise Exercise|104 Videos

Similar Questions

Explore conceptually related problems

For the reaction 2P + Q rarr R, 12 mol of P and 8 mol of Q are taken then:

For the reaction 2P + Q rArr R, 8 mol of p and 5 mol of Q will produce:

Calculate Delta G (in joule) for the reaction 2A(g) to B(g)+C(g) when mixture contains 1 mole of A, 2 moles of B and 1 mole of C at total pressure of 10 atm and 300 K. [Given : G_(m)^(@),A(g)=40 "kJ mol"^(-1) , G_(m)^(@),B(g)=60 "kJ mol"^(-1) , G_(m)^(@),C(g)=20 "kJ mol"^(-1) , R=8.3 JK^(-1)mol^(-1) and "In " 2=0.7 ]

In the reaction 4A + 2B + 3C to A_(4)B_(2) C_(3) , what will be the number moles of product formed starting from one mole of A, 0.6 moles of B and 0.72 moles of C?

In the reaction 4A+2B+ 3C to A_(4)B_(2)C_(3), what will be the number of moles of product formed, starting from 1 mol of A, 0.6 mol of B and 0.76 mol of C :-

For the reaction, A+B hArr 2C, 2 mol of A and 3 mol of B are allowed to react. If the equilibrium constant is 4 at 400^(@)C , what will be the moles of C at equilibrium?

Under S.T.P. 1 mol of N_(2) and 3 mol of H_(2) will form on complete reaction

DISHA PUBLICATION-SOME BASIC CONCEPTS OF CHEMISTRY-Exercise
  1. If potassium chlorate is 80% pure, then 48 g of oxygen would be produc...

    Text Solution

    |

  2. When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixtu...

    Text Solution

    |

  3. Consider the reaction 2 A+B+3C to P+2Q. Starting with 3 mol of A, 2 m...

    Text Solution

    |

  4. A mixture of CO and CO(2) having a volume of 20 mL is mixed with X mL...

    Text Solution

    |

  5. Consider a titration of potassium dichromate solution with acidified M...

    Text Solution

    |

  6. On dividing 0*25 by 22*1176, the actual answer is 0*011303. The correc...

    Text Solution

    |

  7. The number of significant figures for the three numbers 161 cm, 0.161...

    Text Solution

    |

  8. In compound A, 1.00 g nitrogen units with 0.57 g oxygen. In compound B...

    Text Solution

    |

  9. In the final answer of the expression ((29.2-20.2)(1.79xx10^(5)))/1.37...

    Text Solution

    |

  10. Specific volume of cylindrical virus particle is 6.02xx10^(-2) c c//g ...

    Text Solution

    |

  11. The maximum number of molecules is present in

    Text Solution

    |

  12. If N(A) is Avogadro's number then number of valence electrons in 4.2 g...

    Text Solution

    |

  13. 10 g of a metal gives 14 g of its oxide. The equivalent mass of its o...

    Text Solution

    |

  14. MnO(2) on ignition converts into Mn(3)O(4). A sample of pyrolusite hav...

    Text Solution

    |

  15. A 3 L gas mixture of propane (C(3)H(8)) and butane (C(4)H(10)) on comp...

    Text Solution

    |

  16. Glauberite is a mineral containing sodium sulphate (M= 142.0) and cal...

    Text Solution

    |

  17. A mixture of methane and ethane in the molar ratio of x:y has a mean m...

    Text Solution

    |

  18. Antimony reacts with sulphur according to the equation 2Sb(s) + 3S(...

    Text Solution

    |

  19. 10 g CaCO3 were dissolved in 250 ml of 1 M HCl or the solution was boi...

    Text Solution

    |

  20. The concentrated sulphuric acid that is peddled commercially is 95% H(...

    Text Solution

    |