A 3 L gas mixture of propane `(C_(3)H_(8))` and butane `(C_(4)H_(10))` on complete combustion at 25 C produced 10 L `CO_(2.)` Assuming constant P and T conditions what was volume of butane present in initial mixture?

Options

A. 2 : 1
B. 1 : 2
C. 1.5 : 1.5
D. 0.5 : 2.5

Answer

A

Explanation

`underset(a)(C_(3)H_(8))+5O_(2) to underset(3a)(3CO_(2))+4H_(2)O`
`underset((3-a))(C_(4)H_(10))+(13)/(2)O_(2) to underset(4(3-a))(4CO_(2))+5H_(2)O`
But 3a + 4(3 - a) = 10
`:.` a = 2 (Propane) and 3 - 2 = 1 (Butane)