10 g `CaCO_3` were dissolved in 250 ml of 1 M HCl or the solution was boiled. What volume of 2 M KOH would be required to equivalence point after boiling? Assume no change in volume during boiling.

Options

A. 50 mL
B. 25 mL
C. 75 ml
D. 60 mL

Answer

B

Explanation

Meq. of `CaCO_(3)=(10)/(50) xx 1000=200`
Meq. of `HCl=250 xx 1=250`
Meq. of HCl left in the solution=250-200=50
`:.` Meq. of KOH required `V xx 2=50`
`:.` V = 25 mL