The weight of one molecules of a compound ` C_(60)H_(122)` is

Options

A. `1.2 xx 10^(-20) g`
B. `1.4 xx 10^(-21) g`
C. `5.025 xx 10^(23) g`
D. `6.023 xx 10^(23) g`

Answer

B

Explanation

`"Molecule" to C_(69)H_(122)`
Molecular mass of `C_(60)H_(122)`
`[60 xx 12+ 1 xx 122]`
`720+122 to 842`
weight of one molecule of `C_(60)H_(122) = ("molecular Weight of" C_(60)H_(122))/("Avogadro number")`
`= (842)/(6.023 xx 10^(23)) implies 1.4 xx 10^(-21) g`