Home
Class 12
CHEMISTRY
The number of neutrons in dipositive zin...

The number of neutrons in dipositive zinc ion with mass number `70` is.

A

34

B

36

C

38

D

40

Text Solution

Verified by Experts

The correct Answer is:
D
Number of neutrons = Mass number - Atomic number = 70-30=40.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STATES OF MATTER

    DISHA PUBLICATION|Exercise Exercise|104 Videos

  • SURFACE CHEMISTRY

    DISHA PUBLICATION|Exercise Exercise-2 :Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

The number of electrons in a dipositive ion of an element X is 18. If the mass number of X is 4 units more than twice the number of electrons of its ion, calculate the number of protons, electron and neutrons in X.

The number of electrons in a di-positive ion of an element X is 18. If the mass number of X is 4 units more than twice the number of electrons of its ion, calculate of protons , electron and neutrons in X.

Knowledge Check

  • The total number of neutrons in dipositive zinc ions with mass number 65 is

    A
    32
    B
    35
    C
    40
    D
    38

  • The number of neutrons in dipositive zincion ( Zn^(2+) ,mass number 70 and atomic number 30) is -

    A
    34
    B
    36
    C
    38
    D
    40

  • If a dipositve ion of an element 'X' consists of 12 protins and 12 neutrons and another dipositve ion of an element 'Y' consists of 18 electrons and twice the number of electrons of dipositive ion X is the number of neutrons of Y . Then the mass numbers would be in the ratio of

    A
    ` 1 : 2 `
    B
    `3 : 5`
    C
    `12 : 19`
    D
    `2 : 3`

    • Similar Questions

    Explore conceptually related problems

    If .a. is the number of electrons in a dispositive ion and it has three neutrons more than the number of protons, identify the atomic number and mass number.

    If a dispositive ion of an element X consists of 12 protons and 12 neutrons and another dispositive ion of an element Y consists of 18 electrons and twice the number of electrons of dispositive ion X is the number of neutrons of Y, then, the mass number would be in the ratio of

    If a dispositive ion of an element X consists of 12 protons and 12 neutrons and another dispositive ion of an element Y consists of 18 electrons and twice the number of electrons of dispositive ion X is the number of neutrons of Y. Then the mass numbers would be in the ratio of

    If a dispositve ion of an element 'X' consists of 12 protons and 12 neutrons and another dipositve ion of an element 'Y' consists of 18 electrons and twice the number of electrons of dipostive ion X is the number of neutrons of Y. Then the mass number would be in the ratio of

    Identify the number of neutrons present in a pair of element with atomic numbers 20 and 13 , if their mass numbers are 40 and 27 respectively.

    Home
    Profile