Let `m_(p)` be the mass of a poton , `M_(1)` the mass of a `_(10)^(20) Ne` nucleus and `M_(2)` the mass of a `_(20)^(40) Ca` nucleus . Then

Options

A. `M_(2) = 2M_(1)`
B. `M_(1) lt 10(m_(p) + m_(n))`
C. `M_(2) gt 2M_(1)`
D. `M_(1) = M_(2)`

Answer

A

Explanation

`""_(20)^(10)Ne` contains 10 protons and 10 neutrons
`therefore M_(1) = 10 m_(p) + 10m_(n)`
`""_(40)^(20)Ca` contains 20 protons and 20 neutrons .
`therefore M_(2) = 20 m_(p) + 20 m_(n)`
`therefore M_(2) = 2M_(1)`