The energy of an electron in the nth Bohr orbit of hydrogen atom is

Options

A. `-(13.6)/(n^(4))eV`
B. `-(13.6)/(n^(3))eV`
C. `-(13.6)/(n^(2))eV`
D. `-(13.6)/(n)eV`

Answer

C

Explanation

Energy of an electron in Bohr.s orbit is given by the relationship. `E_(n) = - (136.)/(n^(2)) dr = - (ze^(2))/(r)`