When an electron of charge , e and mass , m moves with velocity v around the nuclear charge 'Ze' describing the circular orbit, the potential energy of the electron is

Options

A. `Ze^(2)//r`
B. `-Ze^(2)//r`
C. `Ze^(2)//r`
D. `mv^(2)//r`

Answer

B

Explanation

P.E= work done = ` int_(oo)^(t) - (Ze^(2))/(r^(2)) dr = - (ze^(2))/(r)` .