The potential energy of the electron present in the ground state of ` Li^(2+)` ion is represented by :

Options

A. `(+3e^(2))/(4 pi epsi_(0)r)`
B. `(-3e)/(4 pi epsi_(0)r)`
C. `(-3e^(2))/(4 pi epsi_(0)r^(3))`
D. `(-3e^(2))/(4 pi epsi_(0)r)`

Answer

D

Explanation

In S.I units the `P.E = (-Ze^(2))/(4 pi epsi_(0)r)`. For `Li^(2+)` , Z = 3
`therefore P.E = (-3e^(2))/(4 pi epis_(0)r)`