When electronic transition occurs from higher energy state to lower energy state with energy difference equal to `Delta E` electron volts , the wavelength of the line emitted is approxmately equal to

Options

A. `(12395 )/(Delta E) xx 10^(-10)` m
B. `(12395)/(Delta E) xx 10^(10) m`
C. `(12395)/(DeltaE) xx 10^(-10) cm `
D. `(12395)/(Delta E) xx 10^(10) ` cm

Answer

A

Explanation

`lambda = (h)/(Delta E) `
` = (6.62 xx 10^(-34) J s xx 3 xx 10^(8) ms^(-1))/(E xx 1.602 xx 10^(-19)J)`
` = (12395)/(E) xx 10^(-10)m`