The orbital angular momentum for an electron revolving in an orbit is given by `sqrt(l(l + 1))(h)/(2pi)`. What is the momentum of an s-electron?

Options

A. zero
B. `(h)/(2pi)`
C. `sqrt(2).(h)/(2pi)`
D. `+(1)/(2).(h)/(2pi)`

Answer

A

Explanation

For s- electron , l = 0
`therefore ` Orbital angular momentum `= sqrt(0(0+1))(h)/(2pi) = 0`