An electron in a hydrogen atom in its ground state absorbs 1.5 times as much energy as the minimum required for it to escape from the atom. What is the velocity of the emitted electron?

Options

A. `1.54 xx 10^(6)m//s`
B. `1.54 xx 10^(8) m//s`
C. `1.54 xx 10^(7) C//kg`
D. `1.54 xx 10^(4) m//s`

Answer

A

Explanation

Energy absorbed ` = 13.6 xx 1.5 = 20.4e V` out of this 6.8 eV is converted to K.E
` 6.8 eV rArr 6.8 xx 1.6 xx 10^(-19) J,`
`6.8 xx 1.6 xx 10^(-19) = K.E rArr ((1)/(2)) mv^(2)`
`v = sqrt((2KE)/(m)) = sqrt((2xx1.088 xx 10^(-18))/(9.1 xx 10^(-31)))`
` = 1.54 xx 10^(6) m//s`