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The electronic, identified by quantum nu...

The electronic, identified by quantum numbers n and l, (i) `n = 4, l = 1`, (ii) `n = 4, l = 0`, (iii) `n = 3,l = 2`, (iv) `n = 3, l = 1` can be placed in order of increasing energy, from the lowest to highest, as

A

`(iv) lt (ii) lt (iii) lt (i)`

B

`(ii) lt (iv) lt (i) lt (iii)`

C

`(i) lt (iii) lt (ii) lt (iv)`

D

`(iii) lt (i) lt (iv) lt (ii)`

Text Solution

Verified by Experts

The correct Answer is:
A
Higher the value of (n +1) , the higher is the energy When (n+1) value is the same see value of n.

`therefore (iv) lt (ii) lt (iii) lt (i)`
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The electrons, identified by quantum numbers n and l(i) n=4,l=1 (ii) n=4, l=0 (iii) n=3,l=2 (iv) n=3, l=1 can be placed in order of increasing energy from the lowest to highest as

The electrons identified by quantum numbers n and l : (1) n = 4, l = 1 (2) n = 4, l = 0 (3) n = 3, l = 2 (4) n = 3, l = 1 can be placed in order of increasing energy as :

Knowledge Check

  • The electrons identified by quantum numbers n and l

    A
    n=4 , l=1
    B
    n=4 , l=0
    C
    n=3 , l=2
    D
    n=3 , l=1

  • In an orbital electrons are filled according to Aufbau principle, Pauli's exclusion principle and Hund's rule of maximum muliplicity . According to Aufbau principal the orbital are filled in order to their increasing energies . In the order of increase of energy of orbitals cna be calculated from ( n + l ) rule. Lower the value of ( n + l ) for an orbital the lowest energy hence orbital are filled in order of increasing ( n + l ) value. If two orbitals have same ( n + l ) value, the orbital with lower value of 'n' has lower energy hence it is filled first. According to Pauli's exclusion principle, an orbital can have maximum two electrons with opposite spin. According to Hunds rule pairing of electron in degenerate orbitals of the same sub shell does not take place until each orbital belonging to that sub shell has got one electron each i.e., singly occupied. The electron identified by quantum number n & l (i) n = 4, l = 1 (ii) n = 4, l = 0 ( iii) n = 3, l = 2 (iv) n = 3, l = 1 can be placed in order of increasing energy from the lowest to the highest as

    A
    `(iv) lt (ii) lt (iii) lt (i)`
    B
    `(ii) lt (iv) lt (i) lt (iii) `
    C
    `(i) lt (iii) lt (ii) lt (iv)`
    D
    `(iii) lt (i) lt (iv) lt (ii) `

  • The electrons identified by the following quantum numbers n and l: (i) n = 4, l = 1, (ii) n = 4, l = 0, (iii) n = 3, l = 2 , and (iv) n = 3, l = 1 can be placed in the order of increasing enegry from the lowest to the highest as

    A
    `(iii) lt (i) lt (iv) lt (ii)`
    B
    `(i) lt (iii) lt (ii) lt (iv)`
    C
    `(ii) lt (iv) lt (i) lt (iii)`
    D
    `(iv) lt (ii) lt (iii) lt (i)`

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    the electrons identified by quantum number n and l (i)n=4, l=1 (ii)n=4, l=0 (iii) n=3 , l= 2 and (iv) n=3, l=1 can be placed in order of increasing energy from the lowest to the highest as

    The electrons, identified by quantum numbers n and l (a) n=4, l =1 (b) n= 4, l = 0 (c) n= 3, l = 2 (d) n = 3, l =1 Can be placed in order of increasing energy as :

    The electrons, identified by quantum number n and l: (I) n = 3, l =0 (II) n = 5, l = 2 (III) n = 2,l = 1 (IV) n=4,l = 3 can be placed in order of increasing energy from the lowest to highest as:

    The electrons, identified by quantum number n and l: (I) n = 3, l =0 (II) n = 5, l = 2 (III) n = 2,l = 1 (IV) n=4,l = 3 can be placed in order of increasing energy from the lowest to highest as:

    The electrons, identified by quantum number n and l: (I) n = 3, l =0 (II) n = 5, l = 2 (III) n = 2,l = 1 (IV) n=4,l = 3 can be placed in order of increasing energy from the lowest to highest as:

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