Ground state energy of H-atom is `(-E_(1))`,t he velocity of photoelectrons emitted when photon of energy `E_(2)` strikes stationary `Li^(2+)` ion in ground state will be:

Options

A. `v = sqrt((2(E_(p) - E)/(m))`
B. `v = sqrt((2(E_(p)+9E))/(m))`
C. `v = sqrt((2(E_(p) - 9E))/(m))`
D. `v = sqrt((2(E_(p) -3E))/(m))`

Answer

C

Explanation

work function for `Li^(2+) = 9E`
`E_(p) = W + (1)/(2)mv^(2) ,E_(p) = 9E + (1)/(2)mv^(2)`
`v = sqrt((2(E_(9) - 9E))/(m))`