The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be

Options

A. `lambda_(1) = lambda_(2)`
B. `lambda_(1) = 2lambda_(2)`
C. `lambda_(1) = 4 lambda_(2)`
D. `lambda_(1) = (1)/(2) lambda_(2) `

Answer

B

Explanation

Given `E_(1) = 25eV, E_(2) = 50 eV`
`E_(1) = (hc)/(lambda_(1)), E_(2) =(hc)/(lambda_(2)) " "therefore (E_(1))/(E_(2)) = (lambda_(2))/(lambda_(1))`
`therefore (lambda_(2))/(lambda_(1)) = (25)/(50) =(1)/(2) " " therefore lambda_(1) = 2lambda_(2)`