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The number of geometric isomers that can...

The number of geometric isomers that can exist for square planner complex ion `[Pt(CI)(PY)(NH_(3))(NH_(2)OH)]^(+)` is (Py = pyridine) :

A

4

B

6

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
D
Square planar complexes of type M[ABCD] form three isomers . Their position may be obtained by finxing the position of one ligand and placing at the trans position any one of the remaining three ligands one by one .
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