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The octahedral complex of a metal ion M^...

The octahedral complex of a metal ion `M^(3+)` with four monodentate ligands `L_(1),L_(2),L_(3)` and `L_(4)` absorb wavelengths in the region of red,green, yellow and bule, respectively The increasing order of ligand strengh of the four ligands is

A

`L_4 lt L_3 lt L_2 lt L_1`

B

`L_1 lt L_3 lt L_2 lt L_4`

C

`L_3 lt L_2 lt L_4 lt L_4`

D

`L_1 lt L_2 lt L_4 lt L_3`

Text Solution

Verified by Experts

The correct Answer is:
B

For a given metal ion, weak field ligands create a complex with smaller `Delta`, which will absorbs light of longer `lambda` and thus lower frequency . Conservely , stronger field ligands create a larger `Delta, ` absorb light of shorter `lambda` and thus higher v i.e. higher energy.
`underset(lambda= 6.50nm)("Red") lt underset(570 nm)("Yellow") lt underset(490 nm)("Green") lt underset(450 nm)("Blue")`
So order of ligand strength is
`L_1 lt L_3 lt L_2 lt L_4`
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