The total number possible isomers for the complex compound `[Cu^(II)(NH_(3))_(4) [Pt^(II)CI_(4)]` are

Options

A. 3
B. 6
C. 5
D. 4

Answer

D

Explanation

The total number of isomers for the complex compound
`[Cu^(II) (NH_3)_4 ][Pt^(II)Cl_4]` is four
these four isomers are
`[Cu(NH_3)_3 Cl][Pt(NH_3)Cl_3]`,
`[Cu(NH_3) CL_3 ][Pt(NH_3)_3Cl]`
`[CuCl_4][Pt(NH_3)_4] and [Cu(NH_3)_4][PtCl_4)`
The isomer `[Cu(NH_3)_2 Cl_2]` does not exist because both parts are identical.