The sum of coordination number and oxidation number of the metal M in the complex `[M(en)_2(C_2O_4)]Cl` (where en is ethylenediamine) is:

Options

A. 9
B. 6
C. 7
D. 8

Answer

A

Explanation

`[M (en)_2 (C_2 O_4)]Cl`
`C_2 O_4^(2-)`= bidentate ligand, carry -2 charge
en= bidentate ligand, carry 0 charge
`therefore` M carry + 3 charge, coordination number =6
`therefore ` sum =+3 +6=9