Consider the following complex `[Co(NH_(3))_(5)CO_(3)]ClO_(4)`
The coordination number, oxidation number number of d-electrons and number of unpaired d-electrons on the metal are respectively

Options

A. 6,3,6,0
B. 7,2,7,1
C. 7,1,6,4
D. 6,2,7,3

Answer

A

Explanation

`[Co(NH_3)_5 CO_3]ClO_4` Six monodentate ligands are attached to Co hence C.N. of Co=6
O.N. `=x+5 xx(0) + 1 xx (-2) + 1 xx (-1) =0 therefore x=+3`, electronic configuration of `Co^(3+)[Ar] 3d^6 4s^0` hence number of d electrons is 6. All d electrons are paired due to strong ligand hence unpaired electron is zero .