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Nickel (Z=28) combines with a uninegativ...

Nickel (Z=28) combines with a uninegative monodenatate ligands to form a diamagnetic complex `[NiL_(4)]^(2-)`. The hybridisation involved and the number of unpaired electrons present in the complex are respectively:

A

`sp^3`, two

B

`dsp^2`, zero

C

`dsp^2`, one

D

`sp^3` ,zero

Text Solution

Verified by Experts

The correct Answer is:
A
`[NiL]^(2-)`

i.e. no. of unpaired electron =2
hybridization `-sp^2`
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