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50 ml of 0.2 M solution of a compound wi...

50 ml of 0.2 M solution of a compound with empirical formula `CoCl_(3). 4NH_(3)` on treatment with excess of `AgNO_(3)(aq)` yields 1.435 g of AgCl. Ammonia is not removed by treatment with concentrated `H_(2)SO_(4)`. The formula of the compound is

A

`Co(NH_3)_4 Cl_3`

B

`[Co(NH_3)_4 Cl_2]Cl`

C

`[Co(NH_3)_4]Cl_3`

D

`[CoCl_3(NH_3)](NH_3)_3`

Text Solution

Verified by Experts

The correct Answer is:
B
Magnetic moment indicates that there are three unpaired electrons present in chromium. These must be present in lower energy orbitals which are `3d_(xy), 3d_(yz) and 3d_(xz)`
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