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Two travelling waves y1=Asin[k(x-ct)] an...

Two travelling waves `y_1=Asin[k(x-ct)]` and `y_2=Asin[k(x+ct)]` are superimposed on string. The distance between adjacent nodes is

A

`ct//pi`

B

`ct//2pi`

C

`pi//2k`

D

`pi//k`

Text Solution

Verified by Experts

The correct Answer is:
D
`y=A sin (kx-kct)+A sin (kx+kxt)`
`2A sin (kct).cos kx`
Thus `(2pi)/lamda=k, therefore lamda =(2 pi)/k`
The distance between adjacent nodes `=lamda/2=pi/k`
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