A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of `theta`, where `theta` is the angle by which it has rotated, is given as `ktheta^(2)` If its moment of inertia is I then the angular acceleration of the disc is

Options

A. `(k)/(4I)theta`
B. `(k)/(I)theta`
C. `(k)/(2I)theta`
D. `(2k)/(I)theta`

Answer

d

Explanation

Work done by torque is responsible for change in kinetic energy.
`:. tau= (DE)/(d theta) :. Ialpha= 2Ktheta :. alpha= (2ktheta)/(I)`