A capillary tube of radius `R` is immersed in water and water rises in it a height `H`. Mass of water in capillary tube is `M`. If the radius of the tube is doubled, mass of water that will rise in capillary tube will be

Options

A. M
B. `(M)/(2)`
C. 4M
D. 2M

Answer

d

Explanation

We have, `h= (2Tcostheta)/(rrhog)`
Mass of the water in the capillary
`m= rhoV= rho xx pi r^(2) h= rho xx pi r^(2) xx (2Tcostheta)/(rrhog)`
`implies m prop r`
`:. (m_(1))/(m_(2))= (r)/(2r)`
or `m_(2)= 2m_(1)= 2m`