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When subjected to a force of compression...

When subjected to a force of compression, the length of a bone decreases by `2.7xx10^(-5)m`. When this same bone is subjected to a tensile force of the same magnitude, by how much does it stretch ?

A

`4.6xx10^(-5)m`

B

`1.6xx10^(-5)m`

C

`3.1xx10^(-5)m`

D

`2.0xx10^(-5)m`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find out how much the bone stretches when subjected to a tensile force, given that it compresses by a certain amount under a compressive force. We can use the relationship between compression and tension through Young's modulus. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Compression of the bone: \( \Delta L_c = 2.7 \times 10^{-5} \, \text{m} \) - Young's modulus of compression for the bone: \( Y_c = 9.4 \times 10^9 \, \text{N/m}^2 \) - Young's modulus of tensile strength for the bone: \( Y_t = 1.6 \times 10^{10} \, \text{N/m}^2 \) 2. **Understand the Relationship:** - The amount of stretch (tensile deformation) \( \Delta L_t \) when the same force is applied in tension can be calculated using the ratio of Young's moduli: \[ \Delta L_t = \Delta L_c \cdot \frac{Y_c}{Y_t} \] 3. **Substitute the Values:** - Plug in the values we have: \[ \Delta L_t = (2.7 \times 10^{-5} \, \text{m}) \cdot \frac{9.4 \times 10^9 \, \text{N/m}^2}{1.6 \times 10^{10} \, \text{N/m}^2} \] 4. **Calculate the Ratio of Young's Moduli:** - Calculate \( \frac{Y_c}{Y_t} \): \[ \frac{Y_c}{Y_t} = \frac{9.4 \times 10^9}{1.6 \times 10^{10}} = 0.5875 \] 5. **Calculate the Stretch:** - Now, substitute this ratio back into the equation: \[ \Delta L_t = (2.7 \times 10^{-5} \, \text{m}) \cdot 0.5875 \] - Perform the multiplication: \[ \Delta L_t = 1.58775 \times 10^{-5} \, \text{m} \approx 1.6 \times 10^{-5} \, \text{m} \] 6. **Final Answer:** - The amount by which the bone stretches when subjected to a tensile force of the same magnitude is: \[ \Delta L_t \approx 1.6 \times 10^{-5} \, \text{m} \] ### Conclusion: The bone stretches by approximately \( 1.6 \times 10^{-5} \, \text{m} \) when subjected to a tensile force of the same magnitude.
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