A point charge `q = 1 C` and mass `1 kg` is projected with speed `10 m//s` in the perpendicular direction of unifrom electric field `E = 100 V//m`. The value of latus rectum of the path followed by charged particle (in meter) is :
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Knowledge Check
A charged particle is projected perpendicular to the direction of uniform electric field. It's path in the region of the field will be
A
elliptic
B
linear
C
circular
D
parabolic
A particle of mass m and charge q is thrown in the vertical direction with a velocity v_(0) in a uniform horizontal electric field E . Assuming the gravity force to be negligible ,the equation of the path followed by the particle will be
A
parabola ,`x = ((qE)/(2 mv_(0)^(2)))y^(2)`
B
hyperbola , `x = (qE)/(2 mv_(0)^(2) y)`
C
straight line ,`x = (qEy)/(2mv_(0)^(2))`
D
none of the above
A particel of charge 1 mu C & mass 1 mg moving with a velocity of 4 m//s is subjected to a unifrm electric field of magnitude 300 V m for 10 sece . Then it s final speed cannot be :
A
` 0. 5 m//s`
B
` 5 m//s`
C
` 3 m//s`
D
` 6 m//s`
RESNICK AND HALLIDAY-ELECTRIC CHARGES AND FIELDS-Practice Questions (Integer Type )
