An ideal diatomic gas, with rotation but no oscillation,undergoes an adiabatic compression. Its initial pressure and volume are 1.20 atm and 0.200 m . Its final pressure is 3.60 atm. How much work is done by the gas?

Explanation

To solve the problem of calculating the work done by an ideal diatomic gas during adiabatic compression, we will follow these steps:

### Step 1: Understand the Given Data
We have the following initial and final conditions:
- Initial Pressure, \( P_1 = 1.20 \, \text{atm} \)
- Initial Volume, \( V_1 = 0.200 \, \text{m}^3 \)
- Final Pressure, \( P_2 = 3.60 \, \text{atm} \)

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