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The electric potential at any point on t...

The electric potential at any point on the central axis of a uniformly charged disk is given by Eq. 24-37,
`V= (sigma)/( 2 epsilon_(0)) ( sqrt( z^(2) + R^(2) )- z )`.
Starting with this expression, derive an expression for the electric field at any point on the axis of the disk.

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To derive the expression for the electric field \( E \) at any point on the axis of a uniformly charged disk, we start from the given electric potential \( V \): \[ V = \frac{\sigma}{2 \epsilon_0} \left( \sqrt{z^2 + R^2} - z \right) \] where: - \( \sigma \) is the surface charge density, ...
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Knowledge Check

  • The electric potential at a point (x,y,z) is given by V=-s^(2)

    A
    `vecE=hati(2xy -z^(3))+hatj xy^(2)+hatk 3 z^(2)x `
    B
    `vecE=hati(2xy +z^(3))+hatj x^(2)+hatk 3 xz^(2) `
    C
    `vecE=hati 2xy + hatj (x^(2)+y^(2))+hatk(3xz-y^(2))`
    D
    `vecE=hatiz + hatj xyz+ hatkz^(2)`
  • The electric field strength due to a ring of radius R at a distance x from its centre on the axis of ring carrying charge Q is given by E = (1)/(4 pi epsilon_(0)) (Qx)/((R^(2) + x^(2))^(3//2)) At what distance from the centre will the electric field be maximum ?

    A
    `x = R`
    B
    `x = (R )/(2)`
    C
    `x = +- (R )/(sqrt(2))`
    D
    `x = sqrt(2) R`
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