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A charged, conducting sphere of radius 5...

A charged, conducting sphere of radius 5.5 cm sets up a potential of 75 V at a radial distance of 2.2 m (with V = 0 set at infinity). (a) What is the potential on the sphere's surface? (b) What is the surface charge density ?

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To solve the problem step by step, let's break it down into two parts as given in the question. ### Part (a): Finding the Potential on the Sphere's Surface 1. **Understanding the Potential Formula**: The potential \( V \) at a distance \( r \) from a charged sphere is given by the formula: \[ V = \frac{kQ}{r} \] ...
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Knowledge Check

  • An insulated charged conducting sphere of radius 5cm has a potential of 10V at the surface. What is the potential at centre?

    A
    10V
    B
    zero
    C
    same as that at 5 cms from the surface
    D
    same as that at 25 cms from the surface

  • A sphere of radius 1 cm has potential of 8000 V , then energy density near its surface will be

    A
    `64 xx 10^(5) J//m^(3)`
    B
    `8 xx 10^(3) J//m^(3)`
    C
    `32 J//m^(3)`
    D
    `2.83 J//m^(3)`

  • A sphere of radius 1 cm has potential of 10000V, then energy density near its surface will be

    A
    `64xx10^(5) J//m^(3)`
    B
    `8xx10^(3) J//m^(3)`
    C
    `32 J//m^(3)`
    D
    `4.425 J//m^(3)`

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