A charged, conducting sphere of radius 5.5 cm sets up a potential of 75 V at a radial distance of 2.2 m (with V = 0 set at infinity). (a) What is the potential on the sphere's surface? (b) What is the surface charge density ?

Explanation

To solve the problem step by step, let's break it down into two parts as given in the question.

### Part (a): Finding the Potential on the Sphere's Surface

1. **Understanding the Potential Formula**: The potential \( V \) at a distance \( r \) from a charged sphere is given by the formula:
\[ V = \frac{kQ}{r} \]
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