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x(1) , x(2) , x(3)… . x(50) are fifty re...

`x_(1) , x_(2) , x_(3)`… . `x_(50)` are fifty real numbers such that `x_(r) lt x_(r + 1)` for r = 1 ,2 , 3 …….. , 49 . Five numbers out of these are picked up at random . The probability that the five numbers have `x_(20)` as the middle number is :

A

`(""^(20)C_(2)xx""^(30)C_(2))/(""^(50)C_(5))`

B

`(""^(30)C_(2)xx""^(19)C_(2))/(""^(50)C_(5))`

C

`(""^(19)C_(2)xx""^(31)C_(2))/(""^(50)C_(5))`

D

None of these

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The correct Answer is:
B
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DISHA PUBLICATION-PROBABILITY-1-EXERCISE-1 : CONCEPT BUILDER
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